Fermat's Last Theorem for the case n = 4 #
There are no non-zero integers a, b and c such that a ^ 4 + b ^ 4 = c ^ 4.
Shorthand for three non-zero integers a, b, and c satisfying a ^ 4 + b ^ 4 = c ^ 2.
We will show that no integers satisfy this equation. Clearly Fermat's Last theorem for n = 4
follows.
Instances For
We say a solution to a ^ 4 + b ^ 4 = c ^ 2 is minimal if there is no other solution with
a smaller c (in absolute value).
Equations
- Fermat42.Minimal a b c = (Fermat42 a b c ∧ ∀ (a1 b1 c1 : ℤ), Fermat42 a1 b1 c1 → Int.natAbs c ≤ Int.natAbs c1)
Instances For
if we have a solution to a ^ 4 + b ^ 4 = c ^ 2 then there must be a minimal one.
a minimal solution to a ^ 4 + b ^ 4 = c ^ 2 must have a and b coprime.
We can swap a and b in a minimal solution to a ^ 4 + b ^ 4 = c ^ 2.
We can assume that a minimal solution to a ^ 4 + b ^ 4 = c ^ 2 has positive c.
Fermat's Last Theorem for $n=4$: if a b c : ℕ are all non-zero
then a ^ 4 + b ^ 4 ≠ c ^ 4.
To prove Fermat's Last Theorem, it suffices to prove it for odd prime exponents.