The syntax [a, b, c] is shorthand for a :: b :: c :: [], or
List.cons a (List.cons b (List.cons c List.nil)). It allows conveniently constructing
list literals.
For lists of length at least 64, an alternative desugaring strategy is used
which uses let bindings as intermediates as in
let left := [d, e, f]; a :: b :: c :: left to avoid creating very deep expressions.
Note that this changes the order of evaluation, although it should not be observable
unless you use side effecting operations like dbg_trace.
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- One or more equations did not get rendered due to their size.
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Auxiliary syntax for implementing [$elem,*] list literal syntax.
The syntax %[a,b,c|tail] constructs a value equivalent to a::b::c::tail.
It uses binary partitioning to construct a tree of intermediate let bindings as in
let left := [d, e, f]; a :: b :: c :: left to avoid creating very deep expressions.
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- One or more equations did not get rendered due to their size.
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Auxiliary for List.reverse. List.reverseAux l r = l.reverse ++ r, but it is defined directly.
Equations
- List.reverseAux [] x = x
- List.reverseAux (a :: l) x = List.reverseAux l (a :: x)
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O(|as|). Reverse of a list:
[1, 2, 3, 4].reverse = [4, 3, 2, 1]
Note that because of the "functional but in place" optimization implemented by Lean's compiler, this function works without any allocations provided that the input list is unshared: it simply walks the linked list and reverses all the node pointers.
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- List.reverse as = List.reverseAux as []
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O(|xs|): append two lists. [1, 2, 3] ++ [4, 5] = [1, 2, 3, 4, 5].
It takes time proportional to the first list.
Equations
- List.append [] x = x
- List.append (a :: l) x = a :: List.append l x
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Tail-recursive version of List.append.
Equations
- List.appendTR as bs = List.reverseAux (List.reverse as) bs
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Equations
- List.instEmptyCollectionList = { emptyCollection := [] }
O(|l|). erase l a removes the first occurrence of a from l.
Equations
- List.erase [] x = []
- List.erase (a :: as) x = match a == x with | true => as | false => a :: List.erase as x
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O(i). eraseIdx l i removes the i'th element of the list l.
erase [a, b, c, d, e] 0 = [b, c, d, e]erase [a, b, c, d, e] 1 = [a, c, d, e]erase [a, b, c, d, e] 5 = [a, b, c, d, e]
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- List.eraseIdx [] x = []
- List.eraseIdx (head :: as) 0 = as
- List.eraseIdx (a :: as) (Nat.succ n) = a :: List.eraseIdx as n
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Tail-recursive version of List.map.
Equations
- List.mapTR f as = List.mapTR.loop f as []
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Equations
- List.mapTR.loop f [] x = List.reverse x
- List.mapTR.loop f (a :: as) x = List.mapTR.loop f as (f a :: x)
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O(|l|). filterMap f l takes a function f : α → Option β and applies it to each element of l;
the resulting non-none values are collected to form the output list.
filterMap
(fun x => if x > 2 then some (2 * x) else none)
[1, 2, 5, 2, 7, 7]
= [10, 14, 14]
Equations
- List.filterMap f [] = []
- List.filterMap f (head :: tail) = match f head with | none => List.filterMap f tail | some b => b :: List.filterMap f tail
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O(|l|). filter f l returns the list of elements in l for which f returns true.
filter (· > 2) [1, 2, 5, 2, 7, 7] = [5, 7, 7]
Equations
- List.filter p [] = []
- List.filter p (head :: tail) = match p head with | true => head :: List.filter p tail | false => List.filter p tail
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Tail-recursive version of List.filter.
Equations
- List.filterTR p as = List.filterTR.loop p as []
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Equations
- List.filterTR.loop p [] x = List.reverse x
- List.filterTR.loop p (a :: l) x = match p a with | true => List.filterTR.loop p l (a :: x) | false => List.filterTR.loop p l x
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O(|l|). partition p l calls p on each element of l, partitioning the list into two lists
(l_true, l_false) where l_true has the elements where p was true
and l_false has the elements where p is false.
partition p l = (filter p l, filter (not ∘ p) l), but it is slightly more efficient
since it only has to do one pass over the list.
partition (· > 2) [1, 2, 5, 2, 7, 7] = ([5, 7, 7], [1, 2, 2])
Equations
- List.partition p as = List.partition.loop p as ([], [])
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Equations
- List.partition.loop p [] (bs, cs) = (List.reverse bs, List.reverse cs)
- List.partition.loop p (a :: as) (bs, cs) = match p a with | true => List.partition.loop p as (a :: bs, cs) | false => List.partition.loop p as (bs, a :: cs)
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O(|l|). dropWhile p l removes elements from the list until it finds the first element
for which p returns false; this element and everything after it is returned.
dropWhile (· < 4) [1, 3, 2, 4, 2, 7, 4] = [4, 2, 7, 4]
Equations
- List.dropWhile p [] = []
- List.dropWhile p (head :: tail) = match p head with | true => List.dropWhile p tail | false => head :: tail
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O(|l|). find? p l returns the first element for which p returns true,
or none if no such element is found.
Equations
- List.find? p [] = none
- List.find? p (head :: tail) = match p head with | true => some head | false => List.find? p tail
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O(|l|). findSome? f l applies f to each element of l, and returns the first non-none result.
findSome? (fun x => if x < 5 then some (10 * x) else none) [7, 6, 5, 8, 1, 2, 6] = some 10
Equations
- List.findSome? f [] = none
- List.findSome? f (head :: tail) = match f head with | some b => some b | none => List.findSome? f tail
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O(|l|). replace l a b replaces the first element in the list equal to a with b.
replace [1, 4, 2, 3, 3, 7] 3 6 = [1, 4, 2, 6, 3, 7]replace [1, 4, 2, 3, 3, 7] 5 6 = [1, 4, 2, 3, 3, 7]
Equations
- List.replace [] x✝ x = []
- List.replace (a :: as) x✝ x = match a == x✝ with | true => x :: as | false => a :: List.replace as x✝ x
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O(|l|). elem a l or l.contains a is true if there is an element in l equal to a.
Equations
- List.contains as a = List.elem a as
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a ∈ l is a predicate which asserts that a is in the list l.
Unlike elem, this uses = instead of == and is suited for mathematical reasoning.
a ∈ [x, y, z] ↔ a = x ∨ a = y ∨ a = z
- head: ∀ {α : Type u} {a : α} (as : List α), List.Mem a (a :: as)
The head of a list is a member:
a ∈ a :: as. - tail: ∀ {α : Type u} {a : α} (b : α) {as : List α}, List.Mem a as → List.Mem a (b :: as)
A member of the tail of a list is a member of the list:
a ∈ l → a ∈ b :: l.
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Equations
- List.instMembershipList = { mem := List.Mem }
O(|l|^2). Erase duplicated elements in the list.
Keeps the first occurrence of duplicated elements.
eraseDups [1, 3, 2, 2, 3, 5] = [1, 3, 2, 5]
Equations
- List.eraseDups as = List.eraseDups.loop as []
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Equations
- List.eraseDups.loop [] x = List.reverse x
- List.eraseDups.loop (a :: l) x = match List.elem a x with | true => List.eraseDups.loop l x | false => List.eraseDups.loop l (a :: x)
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O(|l|). Erase repeated adjacent elements. Keeps the first occurrence of each run.
eraseReps [1, 3, 2, 2, 2, 3, 5] = [1, 3, 2, 3, 5]
Equations
- List.eraseReps x = match x with | [] => [] | a :: as => List.eraseReps.loop a as []
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Equations
- List.eraseReps.loop x✝ [] x = List.reverse (x✝ :: x)
- List.eraseReps.loop x✝ (a' :: as) x = match x✝ == a' with | true => List.eraseReps.loop x✝ as x | false => List.eraseReps.loop a' as (x✝ :: x)
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O(|l|). span p l splits the list l into two parts, where the first part
contains the longest initial segment for which p returns true
and the second part is everything else.
span (· > 5) [6, 8, 9, 5, 2, 9] = ([6, 8, 9], [5, 2, 9])span (· > 10) [6, 8, 9, 5, 2, 9] = ([6, 8, 9, 5, 2, 9], [])
Equations
- List.span p as = List.span.loop p as []
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Equations
- List.span.loop p [] x = (List.reverse x, [])
- List.span.loop p (a :: l) x = match p a with | true => List.span.loop p l (a :: x) | false => (List.reverse x, a :: l)
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O(|l|). groupBy R l splits l into chains of elements
such that adjacent elements are related by R.
groupBy (·==·) [1, 1, 2, 2, 2, 3, 2] = [[1, 1], [2, 2, 2], [3], [2]]groupBy (·<·) [1, 2, 5, 4, 5, 1, 4] = [[1, 2, 5], [4, 5], [1, 4]]
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- List.groupBy R x = match x with | [] => [] | a :: as => List.groupBy.loop R as a [] []
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Equations
- List.groupBy.loop R (a :: as) x✝¹ x✝ x = match R x✝¹ a with | true => List.groupBy.loop R as a (x✝¹ :: x✝) x | false => List.groupBy.loop R as a [] (List.reverse (x✝¹ :: x✝) :: x)
- List.groupBy.loop R [] x✝¹ x✝ x = List.reverse (List.reverse (x✝¹ :: x✝) :: x)
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O(|l|). lookup a l treats l : List (α × β) like an association list,
and returns the first β value corresponding to an α value in the list equal to a.
Equations
- List.lookup x [] = none
- List.lookup x ((k, b) :: es) = match x == k with | true => some b | false => List.lookup x es
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O(|xs|). Computes the "set difference" of lists,
by filtering out all elements of xs which are also in ys.
removeAll [1, 1, 5, 1, 2, 4, 5] [1, 2, 2] = [5, 4, 5]
Equations
- List.removeAll xs ys = List.filter (fun (x : α) => List.notElem x ys) xs
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O(|xs|). Returns the longest initial segment of xs for which p returns true.
Equations
- List.takeWhile p [] = []
- List.takeWhile p (head :: tail) = match p head with | true => head :: List.takeWhile p tail | false => []
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O(|l|). Applies function f to all of the elements of the list, from right to left.
foldr f init [a, b, c] = f a <| f b <| f c <| init
Equations
- List.foldr f init [] = init
- List.foldr f init (head :: tail) = f head (List.foldr f init tail)
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O(min |xs| |ys|). Applies f to the two lists in parallel, stopping at the shorter list.
zipWith f [x₁, x₂, x₃] [y₁, y₂, y₃, y₄] = [f x₁ y₁, f x₂ y₂, f x₃ y₃]
Equations
- List.zipWith f (x_2 :: xs) (y :: ys) = f x_2 y :: List.zipWith f xs ys
- List.zipWith f x✝ x = []
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O(min |xs| |ys|). Combines the two lists into a list of pairs, with one element from each list.
The longer list is truncated to match the shorter list.
zip [x₁, x₂, x₃] [y₁, y₂, y₃, y₄] = [(x₁, y₁), (x₂, y₂), (x₃, y₃)]
Equations
- List.zip = List.zipWith Prod.mk
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O(max |xs| |ys|).
Version of List.zipWith that continues to the end of both lists,
passing none to one argument once the shorter list has run out.
Equations
- List.zipWithAll f [] x = List.map (fun (b : β) => f none (some b)) x
- List.zipWithAll f (a :: as) [] = List.map (fun (a : α) => f (some a) none) (a :: as)
- List.zipWithAll f (a :: as) (b :: bs) = f (some a) (some b) :: List.zipWithAll f as bs
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O(|l|). Separates a list of pairs into two lists containing the first components and second components.
unzip [(x₁, y₁), (x₂, y₂), (x₃, y₃)] = ([x₁, x₂, x₃], [y₁, y₂, y₃])
Equations
- List.unzip [] = ([], [])
- List.unzip ((a, b) :: t) = match List.unzip t with | (al, bl) => (a :: al, b :: bl)
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O(n). range n is the numbers from 0 to n exclusive, in increasing order.
range 5 = [0, 1, 2, 3, 4]
Equations
- List.range n = List.range.loop n []
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Equations
- List.range.loop 0 x = x
- List.range.loop (Nat.succ n) x = List.range.loop n (n :: x)
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Equations
- List.iotaTR.go 0 x = List.reverse x
- List.iotaTR.go (Nat.succ n) x = List.iotaTR.go n (Nat.succ n :: x)
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O(|l|). enumFrom n l is like enum but it allows you to specify the initial index.
enumFrom 5 [a, b, c] = [(5, a), (6, b), (7, c)]
Equations
- List.enumFrom x [] = []
- List.enumFrom x (x_2 :: xs) = (x, x_2) :: List.enumFrom (x + 1) xs
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O(|l|). intersperse sep l alternates sep and the elements of l:
intersperse sep [] = []intersperse sep [a] = [a]intersperse sep [a, b] = [a, sep, b]intersperse sep [a, b, c] = [a, sep, b, sep, c]
Equations
- List.intersperse sep [] = []
- List.intersperse sep [x_1] = [x_1]
- List.intersperse sep (x_1 :: xs) = x_1 :: sep :: List.intersperse sep xs
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O(|xs|). intercalate sep xs alternates sep and the elements of xs:
intercalate sep [] = []intercalate sep [a] = aintercalate sep [a, b] = a ++ sep ++ bintercalate sep [a, b, c] = a ++ sep ++ b ++ sep ++ c
Equations
- List.intercalate sep xs = List.join (List.intersperse sep xs)
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bind xs f is the bind operation of the list monad. It applies f to each element of xs
to get a list of lists, and then concatenates them all together.
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The lexicographic order on lists.
[] < a::as, and a::as < b::bs if a < b or if a and b are equivalent and as < bs.
- nil: ∀ {α : Type u} [inst : LT α] (b : α) (bs : List α), List.lt [] (b :: bs)
[]is the smallest element in the order. - head: ∀ {α : Type u} [inst : LT α] {a : α} (as : List α) {b : α} (bs : List α), a < b → List.lt (a :: as) (b :: bs)
If
a < bthena::as < b::bs. - tail: ∀ {α : Type u} [inst : LT α] {a : α} {as : List α} {b : α} {bs : List α},
¬a < b → ¬b < a → List.lt as bs → List.lt (a :: as) (b :: bs)
If
aandbare equivalent andas < bs, thena::as < b::bs.
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- One or more equations did not get rendered due to their size.
- List.hasDecidableLt [] [] = isFalse ⋯
- List.hasDecidableLt [] (head :: tail) = isTrue ⋯
- List.hasDecidableLt (head :: tail) [] = isFalse ⋯
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isPrefixOf l₁ l₂ returns true Iff l₁ is a prefix of l₂.
That is, there exists a t such that l₂ == l₁ ++ t.
Equations
- List.isPrefixOf [] x = true
- List.isPrefixOf x [] = false
- List.isPrefixOf (a :: as) (b :: bs) = (a == b && List.isPrefixOf as bs)
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isPrefixOf? l₁ l₂ returns some t when l₂ == l₁ ++ t.
Equations
- List.isPrefixOf? [] x = some x
- List.isPrefixOf? x [] = none
- List.isPrefixOf? (a :: as) (b :: bs) = if (a == b) = true then List.isPrefixOf? as bs else none
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isSuffixOf l₁ l₂ returns true Iff l₁ is a suffix of l₂.
That is, there exists a t such that l₂ == t ++ l₁.
Equations
- List.isSuffixOf l₁ l₂ = List.isPrefixOf (List.reverse l₁) (List.reverse l₂)
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isSuffixOf? l₁ l₂ returns some t when l₂ == t ++ l₁.
Equations
- List.isSuffixOf? l₁ l₂ = Option.map List.reverse (List.isPrefixOf? (List.reverse l₁) (List.reverse l₂))
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O(min |as| |bs|). Returns true if as and bs have the same length,
and they are pairwise related by eqv.
Equations
- List.isEqv [] [] x = true
- List.isEqv (a :: as) (b :: bs) x = (x a b && List.isEqv as bs x)
- List.isEqv x✝¹ x✝ x = false
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replicate n a is n copies of a:
replicate 5 a = [a, a, a, a, a]
Equations
- List.replicate 0 x = []
- List.replicate (Nat.succ n) x = x :: List.replicate n x
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Tail-recursive version of List.replicate.
Equations
- List.replicateTR n a = List.replicateTR.loop a n []
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Equations
- List.replicateTR.loop a 0 x = x
- List.replicateTR.loop a (Nat.succ n) x = List.replicateTR.loop a n (a :: x)
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Removes the last element of the list.
Equations
- List.dropLast [] = []
- List.dropLast [x_1] = []
- List.dropLast (x_1 :: xs) = x_1 :: List.dropLast xs
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Returns the largest element of the list, if it is not empty.
Equations
- List.maximum? x = match x with | [] => none | a :: as => some (List.foldl max a as)
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Returns the smallest element of the list, if it is not empty.
Equations
- List.minimum? x = match x with | [] => none | a :: as => some (List.foldl min a as)
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Equations
- List.decidableBEx p [] = isFalse ⋯
- List.decidableBEx p (head :: tail) = if h₁ : p head then isTrue ⋯ else match List.decidableBEx p tail with | isTrue h₂ => isTrue ⋯ | isFalse h₂ => isFalse ⋯
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- List.decidableBAll p [] = isTrue ⋯
- List.decidableBAll p (head :: tail) = if h₁ : p head then match List.decidableBAll p tail with | isTrue h₂ => isTrue ⋯ | isFalse h₂ => isFalse ⋯ else isFalse ⋯